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The mathematics of "flash fill"

Doug Kerr

Well-known member
We are often intersted in shots in which ambient light (perhaps sunlight) is present but flash is to be used to fill shadows or to get a "luminance distinction" between the principal subject and the background. (In the latter regard, Will Thompson has called attention to some of Frank Doorhof's work seen on this forum.)

Often the concern is in getting sufficient flash exposure to match the ambient exposure in the way we wish, especially given that, using normal flash technique, we are limited as to how short a shutter time we can use.

I thought it might be worthwhile to review some of the math involved here.

We will use as our "reference result" the situation where the photometric exposure due to the ambient illumination on the main subject is equal to the photometric exposure due to the flash illumination.

In that situation, if the camera exposure is adjusted to produce our "standard" exposure result on the main subject, then on the background, we would have an exposure result one stop down from "standard".

That of course may not correspond to the photographic effect we want, but it is easily understood, and we can work up or down from there.

We will assume operation at ISO 100. The ISO sensitivity doesn't affect the ratios we will discuss here, and the assumption of ISO 100 saves a step here and there when dealing with guide numbers.

We will assume that the ambient sunlight is such that "appropriate" exposure is given by the infamous "sunny 16" rule.

We will also assume that flash-only exposure following the "guide number" doctrine produces a correspondingly-appropriate exposure result.

We will also assume operation with a shutter speed of 1/200 sec (perhaps the fastest at which we can safely assume successful "X-sync" flash operation with a range of flash equipment and typical "35-mm family" dSLR cameras.

So, lets get started.

First, we will consider ambient-only exposure. Thus, for operation at ISO 100, we would expect an exposure of f/16 at 1/100 sec to be "appropriate". For our adopted shutter speed of 1/200 sec, that would require an aperture of f/11.

Next, we will consider a flash-only exposure (however we might make that happen - big black tent, maybe).

With the flash at a distance D from the main subject, and our f/11 aperture, we would want a flash guide number (GN) of 11D (ISO 100 basis). (GN and D need to be in the same units, feet or meters as we might choose.)

So, if we assume the flash unit to be 10 feet from the main subject, we would want a guide number of 110 feet.

For reference, a Canon Speedlite 580EX II flash unit, with its beamwidth set to "50 mm" (intended to cover the field of view of a full-frame 35-mm camera with a 50 mm lens), has a rated maximum guide number (ISO 100) of 138 ft; at the "80 mm" setting, 174 feet.

Now, we don't necessarily know the guide number of our flash setups. Probably all we know is the rated energy storage, expressed in joules (watt-seconds). That is not a measure of any photometric output property of the setup.

The relationship between the energy storage and the factor we really are intersted in, the on-axis luminous intensity-time product (which in fact the guide number tells us, in a special way, based on some assumptions about exposure strategy) is affected by these factors:

• The discharge fraction (the fraction of the stored energy that actually goes into the flash tube before it extinguishes).

• The electric-photometric conversion efficiency of the flash tube.

• The photometric efficiency of the overall setup (involving how much of the light emitted by the tube is not absorbed in the rig).

• The effective beamwidth of the rig (which depends of course on the reflector, light modifier, etc, in use).

The relationship can be expressed as:

GN = k sqrt(E)

where GN is the guide number (ISO 100 basis, assume feet), E is the energy storage, in joules (watt-seconds), and k is the conversion factor (for GN in feet).

The overall conversion factor varies widely.

Manufacturers who state a GN for their monolight units, with the typical small "included" reflector, generally give numbers implying k in the range of about 5 to 6.5. (They of course don't state it that way.)

When light modifiers such as softboxes are involved, k can be much less.

Some rough data from Will Thompson suggests for a setup with softboxes, a k value as small as 1.5 may obtain.

Just as a matter of interest, the Speedlite 580EX II, at its "80 mm" beamwidth setting, would thus broadly correspond to a studio-type monolight, with a small reflector, with an energy storage rating of about 530 J (530 W-s).

Best regards,

Doug
 

Asher Kelman

OPF Owner/Editor-in-Chief
Doug,

I'm not sure you have really integrated the needs of fill in flash with the ambient light. You have, t seems, just prepared the discussion.

Also, I'd guess that the 580 EX II output might be less than equivalent to a Norman at 400 W/S., but that's just my guess.

Asher
 

Doug Kerr

Well-known member
Hi, Asher,

I'm not sure you have really integrated the needs of fill in flash with the ambient light.
No, nor have I solved the problem of global warming, nor of how in Photoshop CS5 to crop an image to a certain set of pixel dimensions. But I did get an apparently-dead hard drive working.

Also, I'd guess that the 580 EX II output might be less than equivalent to a Norman at 400 W/S., but that's just my guess.

By output, do you mean total luminous energy output (lm-s), or the luminous intensity-time product (cd-s) of the beam with some particular kind of reflector and/or modifier in place, or what?

But it would be nice to be able to make one of those comparisons. I may enlist the Norman-meister von Anaheim to do some testing in that regard. I have no idea.

Figures given by Norman on their site suggest a situation comporting with my observations (k of about 5).

They mention, with a 5" reflector, for some modern head, at 400 J (400 W-s), a GN of 95 feet. The "namesake" GN of the 580EX II is 190 feet; at the "50 mm" beamwidth setting, 138 feet.

Perhaps the problem is a discrepancy between Norman and Anglo-Saxon photometric units.

Best regards,

Doug
 

Alain Briot

pro member
Just underpose the subject by one stop and keep the shutter speed below 1/60th and you' ll get a great shot.

I'm sure all that science is accurate, but if I read it it will make my head hurt so bad I won't even want to pick up a camera!
 

Asher Kelman

OPF Owner/Editor-in-Chief
Just underpose the subject by one stop and keep the shutter speed below 1/60th and you' ll get a great shot.

I'm sure all that science is accurate, but if I read it it will make my head hurt so bad I won't even want to pick up a camera!
Alain,

You have the wit of the writer of the first Indiana Jones movie, where he's faced with an opponent, a martial arts monster of a guy, with a massive sword who does a fearsome intimidating show of force before he's about to butcher India Jones in front of a crowd at a market place. Calmy, with a wistful smile, Indy dispatches the brute with one shot from his pistol.

Still, there's more than a few who's like to see how the master's skill plays out!

Asher
 
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